Question

3.2x^2 -5x + 3 = 0 Solve this by competing the square method
​

Answer 1

Answer:

2x^2-5x+3=0

(√2x)^2-2.√2.p+3=0

2√2.p=5

p=5/2√2

(√2x)^2-2.√2.(5/2√2)+(5/2√2)^2-(5/2√2)^2+3=0

{√2x-(5/2√2)}^2-25/8+3=0

{√2x-(5/2√2)}^2-(1/8)=0

{√2x-5/2√2}^2=(1/2√2)^2

√2x-5/2√2=1/2√2

√2x=5/2√2+1/2√2=6/2√2

x=6/(2√2.√2)=3/2

Another solution is

√2x-5/2√2=-1/2√2

√2x=5/2√2-1/2√2=4/2√2

x=4/(2√2.√2)=1

Step-by-step explanation:

.