Question

3
(-2x^2y)^3. -----------------
(6xy^2)^2​

Answer 1

Answer:

-2/3x^4y^-1

Step-by-step explanation:

minus 2 by 9 x to the power 4 x y to the power minus 1

Answer 2

$\huge \tt \leadsto \frac{ (- 2 {x}^{2} y)^{3} }{(6 {xy}^{2})^{2} }$

$\huge \tt \leadsto \frac{ (- 2 {x}^{2} {y}^{3}) }{6xy^{4} }$