(3) 2x - 3y=9; 2x + y = 13
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2x – 3y = 9 .....(I)
2x + y = 13 .....(II)
Subtracting (II) from (I) we get
– 3y − y = 9 − 13
⇒−4y=−4⇒y=1
Putting this value in (I) we get
2x−3(1)=9⇒2x=9+3=12⇒x=122=6
Thus, (x, y) = (6, 1)
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