Question

3^2x+78=9^2x+1 find x value

Answer 1

3^2x+78 = 9^2x+1

3^2x+78 = 3^2{2x+1}

2x + 78 = 4x + 2

2x = 76

x = 38

HOPE IT HELPS!!!

PLS MARK IT BRAINLIEST

Answer 2

x=2

Explanation:

92x−1=32.(2x−1)

=34x−2

27x=33x

4(2X+1)+4(X+1)=80

42X∗4+4X∗4=80

42X+4X=20

42X+4X=4∗5

4X(4X+1)=41(41+1)

Both LHS & RHS are similar; X = 1

We can rewrite the equation: 4*(4^(2x)+4^(x))=4^(2)*5 => 4^(2x)+4^(x)=4*5.

Let 4^(x)=y, and we have y^(2)+y=20 or (y-4)(y+5)=0 therefor y=4 or y=-5.

Let take y=4, and we have 4^(x)=4^(1) => x= c is the best answer.