3(2x+y)=7xy; 3(x+3y)=11xy by elemination method
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Answer:
x = 1 and y = 3/2
Step-by-step explanation:
3(2x+y) = 7xy
6x + 3y = 7xy ---------(1)
3(x+3y) = 11xy
3x + 9y = 11xy ---------(2)
on multiply by 3 in eq 2
2(3x + 9y = 11xy)
6x + 18y = 22xy -------(3)
on subtract eq 1 and 3
6x + 3y = 7xy
6x + 18y = 22xy
- - -
-15y = -15xy
15y = 15xy
15y/15y = x
1 = x
put x in eq 1
6x + 3y = 7xy
6(1) + 3y = 7(1)y
6 + 3y = 7y
6 = 7y - 3y
6 = 4y
6/4 = y
3/2 = y
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