(3-2xy-y^2)dx-(x+y)^2dy=0 solve it
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dy(x+y)^2=(3-2x-y^2)DX
now
dy/DX=(x+y)^2/(3-2x-y^2)
u can find it by using formula of u/v
now
dy/DX=(x+y)^2/(3-2x-y^2)
u can find it by using formula of u/v
Sudip5678:
please sand me photos of the complet math
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