Question

(-3/2xyz2-9/4xy³z³)by-8/27xyz​

Answer 1

Answer:

$( \frac{ - 3}{ {2xyz}^{2} } - \frac{9}{ {4xy}^{3} {z}^{3} } ) \div \frac{ - 8}{27xyz} \\ = ( \frac{ - 3}{ {2xyz}^{2} } - \frac{9}{ {4xy}^{3} {z}^{3} } ) \times \frac{ - 27xyz}{8} \\ = \frac{ 81}{ {16xyz}^{2} } + \frac{243}{ {32xy}^{3} {z}^{3} } \\ = \frac{162 {y}^{2}z + 243}{{32xy}^{3} {z}^{3}}$