Question

3×-2y=3 ,2×+y=16 find the value of determinants in the given equation​

Answer 1

Answer:

3x-2y=3,2x+y=16

xy=3,3xy=16

3xy-xy, 16-3

2xy=13

Answer 2

Answer:

x = 5

y = 6

Step-by-step explanation:

3x - 2y = 3...(i)

2x + y = 16...(ii)

Now multiply equation (i) by 2 and (ii) by 3

2 × (3x - 2y = 3)

= 6x - 4y = 6....(iii)

3 × (2x + y = 16)

= 6x + 3y = 48....(iv)

Then subtract equation (iv) from (iii)

6x - 4y = 6

- 6x ±3y = ±48

0 -7y = -42

Now solve this equation.

-7y = 42

=> y = -42/-7

=> y = 6

Now put the value of y in equation (i)

3x - 2y = 3

=> 3x - 2(6) = 3

=> 3x - 12 = 3

=> 3x = 3+12

=> 3x = 15

=> x = 15/3

=> x = 5

Hence y = 6 and x = 5

hope it helps.