3×+2y=3 3×-4y=27 solve for × and y
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3×+2y=3.......(1) 3×-4y=27..........(2)
By elimination method,
subtracting (2) equation from (1) , we get
3x+2y -(3x-4y) = 3-27
3x+2y-3x+4y = -24
6y= -24
y= -24/6
y= -4
putting this value in equation (1), we get
3x+2(-4) = 3
3x-8= 3
3x= 3+8
3x= 11
x= 11/3
Hence the value of x and y are 11/3 and -4
Hope it's help you
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