Math, asked by krantikarprathmesh, 9 months ago

(3) 2y2 +27+ 13 = 0​

Answers

Answered by Uriyella
6

Correct Question :–

Solve the quadratic equation by factorisation 2y² + 27y + 13 = 0.

Given :–

  • A quadratic equation = 2y² + 27y + 13 = 0.

Required :–

  • Solve the given quadratic equation by factorisation.

Solution :–

Given quadratic equation,

⟹ 2y² + 27y + 13 = 0

Splitting the middle term.

⟹ 2y² + 26y + y + 13 = 0

⟹ 2y(y + 13) + 1(y + 13) = 0

⟹ (2y + 1) (y + 13) = 0

⟹ (2y + 1) = 0 or (y + 13) = 0

⟹ 2y = –1 or y = –13

⟹ y =  \dfrac{-1}{2} or y = –13

Hence,

 \dfrac{-1}{2} and –13 are roots of the given quadratic equation.

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