3√3х2 +16х +73 = 0 find the roots of each of the following quadratic equations
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3 root3x²+16x+73=0
a=3root3 b=16 c=73
D=b²-4ac
=16²-4×3root3×73
=256-1517.27=126.27
x=-b+rootD/2a or -b-rootD/2a
=-16+root126.27/2(3root3) or -16-root126.27/2(3root3)
=-16+35.51/10.39 or -16-35.51/10.39
=19.51/10.39 or -51.51/10.39
=1.87 or -4.9
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