Question

3✓3+2✓2
/
3✓3-2✓2
RATIONALISE THE FOLLOWING
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Answer 1

Answer:

$=>\frac{35+12\sqrt{6} }{19}$

Step-by-step explanation:

∵Rationalizing factor of denominator ${3\sqrt{3} -2\sqrt{2} } ={3\sqrt{3} +2\sqrt{2} }$

∴$\frac{3\sqrt{3} +2\sqrt{2} }{3\sqrt{3}-2 \sqrt{2} } =\frac{3\sqrt{3}+2 \sqrt{2} }{3\sqrt{3}-2 \sqrt{2}} *\frac{3\sqrt{3} +2\sqrt{2} }{3\sqrt{3} +2\sqrt{2} }$

                $=\frac{9*3+4*2+2*3\sqrt{3}*2 \sqrt{2} }{(3\sqrt{3} )^{2}-(2\sqrt{2} )^{2} }$

                $=\frac{27+8+12\sqrt{6} }{27-8}$

                $=>\frac{35+12\sqrt{6} }{19}$

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