Question

(-π)^3+3(-π)^2+3(-π)+1 solve the problem step by step

Answer 1

(-π)^3 - 3(-π)^2 + 3(-π) + 1 =
-π^3 - 3π^2 - 3π + 1
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Answer 2

Answer:

Step-by-step explanation:

Given

Let us consider π as x

(-π)^3 - 3(-π)^2 + 3(-π) + 1

or, -π^3 - 3π^2 - 3π + 1

Put π = 0

(0)³- 3(0)-3(0)+1

= 1

Put the random values on the equation until the answer is 0, if you get such number divide it by the polynomial to get the quadratic equation as quotient.