Question

3,3+ √2, 3+2√2 ,3+3√3,....

a2- a1 == 3+√2-3 =√2
a3- a2 =(3+2√2 ) -(3+√2) =√2
a4- a3 =( 3+3√2 ) - (3+2√2 ) =√2

so the give number forms an AP with
d=√2

(3+2√2)+ √2 = 3+4√2
(3+4√2 ) + √2 =3+5√2
(3+5√2) +√2 = 3+6√2​

Answer 1

your question is wrong please correct