Question

(3/3)‐² ×(3° -3-1) please answer the question ​

Answer 1

$\huge\mathcal\pink{Answer:-}$

Here it is easy, also, to put the equation into a standard form: Ax² + Bx + C = 0 .

Just multiply the binomial and subtract 169 = 13², like so:

(x+3)² = x² + 6x + 9 = 169

(1)•x² + (6) • x + (9 - 169) = 0.

This gives A = 1, B = 6, and C = -160.

Now if you want to apply the quadratic formula, it is a matter of substituting these values for A, B, and, C, in the formula:

x =−3 ± 13

Giving x = 10 , or, x = -16 .

Of course, recognizing that x + 3 = ±13 , sends this process to the tail end. But, the question asks for something specific, and I hope this provides what you need.

Answer 2

Answer:

$\frac{3}{3} {}^{ - 2} \times (3 {}^{0} - 3 - 1) \\ \frac{3}{3} = \frac{1}{1} = 1 \\ {(1)}^{ - 2} = \frac{1}{1 ^{2} } = \frac{1}{1} = 1 \\ hence \: 1 \times ( {3}^{0} - 4) \\ 3 {}^{0} = 1 \\ 1 \times (1 - 4) \\ 1 \times ( - 3) = - 3$

The answer of this question is -3

Hope my answer helps you friend :-)

I am pretty sure about the answer