Question

3) 3.25 XIU'J
4) 1.25 XIUJ
16. 2 moles of hydrogen is heated at
constant volume. The temperature of the
gas is increased from 280 K to 320 K. If
the specific heat of hydrogen at constant
volume is 10.183 kJ/kg K, find the amount
of heat absorbed in kJ. (Molecular weight
of hydrogen = 2.016)
1) 1.642 2) 2.12 3) 1.821 4) 1.12

Answer 1

(i) At very low temperature, the number of degrees of freedom (DOF) is 3.

U = (3/2) mRT

Cv = (3/2) R and Cp = (5/2) R

So, γ = Cp/ Cv = 5/3 = 1.67

(ii) At medium temperature, the number of degrees of freedom (DOF) is 5.

U = (5/2) mRT

Cv = (5/2) R and Cp = (7/2) R

So, γ = Cp/ Cv = 7/5 = 1.4

(iii) At high temperature, the number of degrees of freedom (DOF) is 7.

U = (7/2) mRT

Cv = (7/2) R and Cp = (9/2) R

So, γ = Cp/ Cv = 9/7 = 1.29

Difference Between two Specific Heat Capacities – (Mayer’s Formula)

(a) Cp - Cv = R/J

(b) For 1 g of gas, cp - cv = r/J

(c)Adiabatic gas constant, γ = Cp/ Cv = cp/ cv

so the answer is 3) 1.821

Answer 2

Answer:

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