Question

3(3 - 2q)(3q+3)(q-2)

Answer 1

Answer:

[3(3 - 2q)] [(3q+3)(q-2)]

= (9- 6q) [3q(q-2) + 3(q-2)]

= (9- 6q) (3q²-6q+ 3q- 6)

= (9- 6q) (3q²-3q-6)

= 9(3q²-3q-6) -6q(3q²-3q-6)

= 27q²- 27q- 54- 18q³+ 18q²+ 36q

= 45q²+ 9q- 54- 18q³

Step-by-step explanation:

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