Math, asked by shobhit1508200697, 9 months ago

(3+√3) (3-√2) = .......................

Answers

Answered by ahanatarafder06
0

Answer:

Answer: (3+√3) (3-√2)

Answer: (3+√3) (3-√2) = (3)² - 3√2 + 3√3 - √3 × √2

Answer: (3+√3) (3-√2) = (3)² - 3√2 + 3√3 - √3 × √2= 9 - 3√2 + 3√3 - √6

Answered by ptl
0

Step-by-step explanation:

(3 +  \sqrt{3} )(3 -  \sqrt{2} ) \\  = 3 \times 3 - 3 \sqrt{2}  + 3 \sqrt{3}  -  \sqrt{3}  \sqrt{2}  \\  = 9  + 3 \sqrt{3}  - 3 \sqrt{2}  -  \sqrt{6}

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