Question

(3+√3) (3-√2) equals

Answer 1

Step-by-step explanation:

$(3 + \sqrt{3} )(3 - \sqrt{2} ) \\ 9 - 3 \sqrt{2} + 3 \sqrt{3} - \sqrt{6}$

Answer 2

Given:

Consider the given $(3+\sqrt{3})(3-\sqrt{2})$

Find:

the value of the given

Solution:

If we have two factors are given ( a + b ) and ( c+ d) then the product will be

(a + b) (c + d) = ac + ad + bc + bd

Therefore

$(3+\sqrt{3})(3-\sqrt{2})=9-3\sqrt{2}+3\sqrt{3}-\sqrt{6}$

since irrational numbers can not be add so this is the final answer.