Question

3-[3-3×{3-(3-3)}]÷3
pls solve and add pic​

Answer 1

$3 - (3 - 3 \times (3 - (3 - 3))) \div 3 \\ \\ 3 - (0 \times (3 - (0))) \div 3 \\ \\ 3 - (0 \times 3) \div 3 \\ 3 - 0 \div 3 \\ \\ 3 \div 3 \\ \\ = 1$

Answer 2

Answer:

5

Step-by-step explanation:

3-[3-3×{3-(3-3)}]÷3

3-[3-3×{3-0}]÷3

3-[3-3×3]÷3

3-[3-9]÷3

3-(-6)÷3

3-(-2)=3+2=5

plz mark brainliest