(3+3×3÷3-3/3)hole to the power 3
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Answered by
0
Answer:
0
Step-by-step explanation:
By BODMAS rule, first solve bracket:
3+3*3/3-3/3
From BODMAS again, solve division first, then multiplication, then addition and then subtraction:
∴, 3+3*3/3-3/3 = 3+3*1-1 = (3+3)*(1-1) = 6*0 = 0
Then, 0 to the power 3 = 0
Hope it helped, please mark as brainliest answer.
Answered by
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Answer:
125 hope this helped
Step-by-step explanation:
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