Question

х3х3 ху
3х ух у
ку - 4 у
- 4у
1
(0) (p?q" - р*q3) = p?q3.
Sol.
(і) (5х2 – 6x) + 3x
(5х2 – 6x) = 3х
5х2 – 6х
3х
5х2 6x 5
lqr2
qr2
—
x – 2
3х
3х
xpxqxqxxxxxx
1xqxxxx
qxr
(5х – 6)
3
(ii) (3y8 – 4ув + 5y4) + y4
(3y8 – 4ув + 5y4) = y4
3ys - 4 y + Бу
4
qr
у
су2 3
3ys 4 y6 54
—​

Answer 1

Answer:

the questions was wrong

Step-by-step explanation:

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