Question

3
3
3
If hk are the perpendicular distances from
(1,2,3) to the x-axis, z-axis respectively then hk=
1) 65
2) 13
3) 15
4) J65​

Answer 1

Answer:

The perpendicular distance of the point (1,2,3) from x axis will be

h=

(y

2

+z

2

)

=

(2)

2

+(3)

2

=

4+9

=

13

The perpendicular distance of the point (1,2,3) from z axis will be

k=

(x

2

+y

2

)

=

(1)

2

+(2)

2

=

1+4

=

5

⇒ hk=

13

.

5

=

65