Question

3(3-4)/15-(3-5)/10=2(3-3)/5​

Answer 1

Answer:

0

Step-by-step explanation:

$\frac{3(3-4)}{15} - \frac{(3-5)}{10} = \frac{2(3-3)}{5}$

Solving L.H.S

$=\frac{3(3-4)}{15} - \frac{(3-5)}{10} \\\\=\frac{1(3-4)}{5} - \frac{(-2)}{10} \\\\= \frac{1(-1)}{5} - \frac{(-1)}{5} \\\\= \frac{-1}{5} + \frac{1}{5} \\\\= 0$

Solving R.H.S

$=\frac{2(3-3)}{5} \\\\=\frac{2(0)}{5} \\\\=\frac{0}{5} \\\\= 0$

Therefore, L.H.S = R.H.S