Question

=(3+3,4+4) =(6,8)
Find the value of ‘k’if the points (4,k),(2,3) are conjugate with respect to x2 + y2 =17
Given A (41)​

Answer 1

Answer:

Since points (1,3) and (2,k) are conjugate w.r.t. the given circle, both the points lie on the polar of the other point.

∴(1,3) lies on x(2)+y(k)−35=0

i.e. 2×1+3×k−35=0

∴3k=33 or k=11