Question

(-3) + 3 + (-4) + (-5) + 4 + 5 integers pls help

Answer 1

Answer:

FIRST OF ALL OPEN THE BRACKETS

3 - 3 -4 -5 + 4 + 5

NOW CANCEL ALL THE TERMS THAT ARE POSSIBLE

THE ANSWER COMES OUT TO BE 0.

PLZ MARK ME AS BRAINLIEST

Answer 2

Solution:

$(-3) + 3 + (-4) + (-5) + 4 + 5$

$=-3+3-4-5+4+5$

$=-3-4-5+3+4+5$

$=-12+12$

$=0$