3,3,4,5 ans63 and 4,4,3,8 ans51 then 9,7,5,9 ans should be option area) 57 b) 53 c) 105d) 111
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Let us get a logic from the problems first:
1st one.
3 | 3 | 4 | 5 = 63
>> 3 + 3 + 4 + 5 = 15 × 2
= 30 - 2² - 5
= 21 × 3
= 63
2nd one.
8 | 4 | 4 | 3 = 51
>> 8 + 4 + 4 + 3 = 19 × 2
= 38 - 4² - 5
= 17 × 3
= 51
We go with the same approach for the next term:
3rd one.
9 | 7 | 5 | 9 = ?
>> 9 + 7 + 5 + 9 = 30 × 2
= 60 - 6² - 5
= 19 × 3
= 57
Therefore, 9 | 7 | 5 | 9 = 57
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