Question

3..3.42 g of sucrose are dissolved in 18 g of water in a beaker. The numbers of oxygen atoms in the solution are:Full Marks : 1 (a) 6.68 ×1023  b) 6.09 ×1022  (c) 6.022 ×1023  (d) 6.022 ×1021​

Answer 1

Answer:

Solution

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Correct option is A)

Molar mass of sucrose = 342 g

No. of oxygen atoms in 342 g of (C

H

22

O

11

) =11×N

A

∴ No. of oxygen atoms in 3.42 g of (C

12

H

22

O

11

) =

342

11×N

A

×3.42

= 0.11N

A

No. of oxygen atoms in 18g of H

2

O =1N

A

∴ Total no. of oxygen atoms in 3.42g of sucrose and 18g of water =0.11N

A

+1N

A

=1.11N

A

=1.11×6.02×10

23

=6.68×10

23

.