Question

3
36. Find the equation of plane passing through the line of intersection
of planes 3x+2y+52–9=0 and x-2y+32+4=0 and the point (6,2,1).
Also find the point of intersection of the plane so obtained and the
line P =(i+2ſ + k)+(2i+j+3k) 71+64-777-0 0​

Answer 1

Step-by-step explanation:

Hint: You found that the point (3,4,−1) lies on both planes, hence lies on the line of intersection, hence lies on the plane that you are interested in. Thus, the equation of the plane is −2x+y−5z=3. The answer −2x+y−5z=3 is the right answer