Question

(3) نصف دائرے میں توسی زاویے کی پیانش کتنی ہوتی ہے؟
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Answer 1

Answer:

aa jo bhi ho vo hindi ya english bhasha me likhe apna answer

Answer 2

Answer:

Draw a circle and its diameter as AB and mark the center as O.

Take any point C on the circumference. So C is in the semicircle. Join CA and CB. Also join CO. Triangle ACO is an isosceles triangle with OA=OC (being radii), therefore Angle OAC = Angle OCA = say x. Similarly, Triangle BCO is an isosceles triangle with OB=OC (being radii), therefore Angle OBC = Angle OCB = say y. Therefore 2x + 2y = 180 degrees. So angle ACB = x+y = 90 degrees. Hence the angle in the semicircle is a right angle