Question

(3+3w+5w2)6 + (2+6w+2w2)3=128
​

Answer 1

Answer:

you have tell the answer also

128

Answer 2

Answer:

3(-3+√113)/18 , -3(3+√113)/18

Step-by-step explanation:

(3+3w+5w2)6 + (2+6w+2w2)3=128

(3+3w+5w2)6=18+18w+30w²

(2+6w+2w2)3=6+18w+6w²

(18+18w+30w²)+(6+18w+6w²)=128

18+18w+30w²+6+18w+6w²=128

30w²+6w²+18w+18w+18+6=128

36w²+36w+24=128

36w²+36w=128-24

36w²+36w=104

36w²+36w-104=0==>divided by 4

9w²+9w-26=0

a=9

b=9

c=-26

-b±$\sqrt{b^{2}-4ac }$/2a

-9±$\sqrt{9^{2}-4(9)(-26) }$/2a

-9±$\sqrt{81-4(-234) }$/2a

-9±$\sqrt{81+936 }$/2a

-9±$\sqrt{1017 }$/2a

-9±3√113/2a

-9+3√113/2×9, -9-3√113/2×9

3(-3+√113)/18 , -3(3+√113)/18