Question

-3(3x-2) +2(3x-2)(3x-2) - 5 factorise

Answer 1

$\bf\tiny{ - 3(3x - 2) + 2(3x - 2)(3x - 2) - 5 } \\ \bf\tiny{3x - 2[ - 3 + 2(3x - 2) - 5]} \\ \bf \tiny{ 3x - 2[ - 8 + 6x - 4]} \\ \bf \tiny{3x - 2(6x - 12}) \\ \\ \sf \red{ 2(3x - 2)(3x - 6)}$

• Maark BRAINLIEST

• Follow me for such content**

Answer 2

Given,

-3(3x-2) +2(3x-2)(3x-2) - 5

= (3x-2)[-3+2(3x-2)]-5

= (3x-2)(-3 + 6x -4)-5

= (3x-2)(6x-7)-5

= (3x-2)(6x-7-5)

= (3x-2)(6x-12)

Thus after factorising [-3(3x-2) +2(3x-2)(3x-2) - 5]

, we get the factors as (3x-2) and (6x-12).