English, asked by aryanbansalu686, 11 months ago

(3^3x*3^2x)/(3^x)=^4√3^20. find value of x​

Answers

Answered by aman2yadav123456
2

Answer:

x=5/4

Explanation:

(3^3x+2x)/(3^x)=3^20/4

3^5x/3^x=3^5

3^5x-x =3^5

3^4x=3^5

4x=5

x=5/4

Answered by Mantsha4305
2

HEY MATE !!

HERE IS YOUR ANSWER..

 \frac{ {3}^{3x}\times {3}^{2x} }{ {3}^{x} }  =  {3}^{ \frac{20}{4} }  \\  \\  \frac{ {3}^{3x + 2x} }{ {3}^{x} }  =  {3}^{5}  \\  \\   \frac{ {3}^{5x} }{ {3}^{x} }  =  {3}^{5}  \\  \\  {3}^{5x - x}  =  {3}^{5}  \\  {3}^{4x}  =  {3}^{5}  \\ 4x = 5 \\ x =  \frac{5}{4}  \\  \\ this \: is \: your \: answer.

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