Question

3√3x^3-5√5y^3
Factorise it

Answer 1

$3 \sqrt{3} = ( { \sqrt{3} )}^{3} \\ 5\sqrt{5} = ( { \sqrt{5} )}^{3} \\ so \: write \: that \: polynomial \: as \\ \: ( { \sqrt{3}x) }^{3} - ( { \sqrt{5}y) }^{3} \: \\ apply \: the \: identity \\ ( {a)}^{3} - ( {b)}^{3} = (a - b)( {a}^{2} + ab + {b}^{2} ) \\ ( { \sqrt{3}x) }^{3} - ( { \sqrt{5}y) }^{3} = ( \sqrt{3} x - \sqrt{5} y)(( { \sqrt{3}x) }^{2} + ( \sqrt{3} x)( \sqrt{5} y) + ( { \sqrt{5}y }^{2} ) \\ = ( \sqrt{3} x - \sqrt{5} y)(3 {x}^{2} + \sqrt{15} xy + 5 {y}^{2} )$

Answer 2

Answer:

BY MUSKAAN MISHRA