√3(-√3y/√2) - √8y = 0
Simplify this, I am unable to understand this, I know I am very weak in maths but please every step is needed.
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√3×-√3/√2-8y
-3/√2-√2×2×2y
-3/√2-2√2y
-3y/√2 -2√2y=0
-3y-4y/√2=0
-7y=0
y=0
is your answer
-3/√2-√2×2×2y
-3/√2-2√2y
-3y/√2 -2√2y=0
-3y-4y/√2=0
-7y=0
y=0
is your answer
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