Math, asked by harilalprasad923, 5 months ago

Зу (у + 3) + бу (3y+9)​

Answers

Answered by madhavmp06
0

Answer:

21y²+63y

Step-by-step explanation:

Зу (у + 3) + бу (3y+9)

3y²+9y+18y²+54y=

21y²+63y

Answered by jayasriskp
0

Answer:

 21y^2 + 60y

Step-by-step explanation:

3y (y + 3) = 3y x y = 3y^{2} and 3y x 3 = 6y =

6y (3y + 9) = 6y x 3y = 18y^2 and 6y x 9 = 54y =

3y^{2} + 6y + 18y^2 + 54y

= 3y^2 + 18y^2 = 21y^2

and 6y + 54y = 60y

21y^2 + 60y

Mark Brainliest if helped!

Tq dear frnd!! :)

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