Question

[(3/4)^-1]^-2÷(16/9)^-1 please bhai and bhan answer do jaldi sa muje answer to dhyan ha 1 answer ha muje pura solution chaiya ​

Answer 1

1

Step-by-step explanation:

[(3/4)^-1]^-2 ÷ (16/9)^-1

= [(3/4)^-1]^-2 ÷ [(4/3)²]^-1

$((a)^{m})^{n} = a^{mn} \\(a/b)^{-m} = (b/a)^{m}$

= [(3/4)]² ÷ [(4/3)^-2]

= [(3/4)]² ÷ [(3/4)]²

$a^{m} / a^{n} = a^{m-n}\\a^{0} = 1$

= [(3/4)]²-²

= 3/4^0

= 1