3,4=11 9,6=64 12,8=63 12,10=??
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Let f(x,y)=ax+by+c
63=12a+8b+c ( we got this from equation 1)
11=3a+4b+c (we got this from equation 2)
64=9a+6b+c ( we got this from equation 3)
When we solve all 3 equations in terms of a,b,c we will get this:
a = 18,
b = − 27.5,
c = 67
f (x,y) = 18 x − 27 . 5 y + 67
f(10,12)=18(10)−27.5(12)+67
f(10,12)=180–330+67
f(10,12)=−113
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