3/4,2/7,3/8 verify using distributive property - a×(b+c)= a×b + a×c
Answers
Step-by-step explanation:
Given x3 -2x2y + 3xy2– y3, 2x3– 5xy2 + 3x2y – 4y3 Collecting positive and negative like terms together, we get = x3 +2x3 – 2x2y + 3x2y + 3xy2 – 5xy2 – y3– 4y3 = 3x3 + x2y – 2xy2 – 5y3 (ii) Given a4 – 2a3b + 3ab3 + 4a2b2 + 3b4, – 2a4 – 5ab3 + 7a3b – 6a2b2 + b4 = a4 – 2a3b + 3ab3 + 4a2b2 + 3b4 – 2a4 – 5ab3 + 7a3b – 6a2b2 + b4 Collecting positive and negative like terms together, we get = a4 – 2a4– 2a3b + 7a3b + 3ab3 – 5ab3 + 4a2b2 – 6a2b2 + 3b4 + b4 = – a4 + 5a3b – 2ab3 – 2a2b2 + 4b4Read more on Sarthaks.com - https://www.sarthaks.com/682903/add-the-following-expressions-i-x-3-2x-2y-3xy-2-y-3-2x-3-5xy-2-3x-2y-4y-3?show=682905#a682905
Step-by-step explanation:
Let a = 3/4,b =2/7,c=3/8
a×(b+c)= 3/4×2/7×3/8
=18/224
= 9/112 ----------- 1
a×b =3/4×2/7
= 6/28
= 3/14
a×c = 3/4 × 3/8
= 9/32
a×b + a×c =3/14 +9/32
=(96+126)/448
= 222/448
= 111/224 --------2
it is not equal
a×(b+c) not equal toa×b + a×c