Question

(3^-4/2^-8)^1/4. pls solve it write now​

Answer 1

4/3

Step-by-step explanation:

$( \frac{ {3}^{ - 4} }{ {2}^{ - 8} } )^{ \frac{1}{4} } \\ = ( \frac{ {2}^{8} }{ {3}^{4} } )^{ \frac{1}{4} } \\ = \frac{( {2}^{8})^{ \frac{1}{4} } }{( {3}^{4} {)}^{ \frac{1}{4} } } \\ = \frac{( {2}^{8 \times \frac{1}{4} } )}{ {3}^{4 \times \frac{1}{4} } } \\ = \frac{{2}^{2}}{ {3}^{1} } \\ = \frac{4}{3}$