Question

(3√4)^(2x+1)=1/32, find x​

Answer 1

Question:

(3√4)^2x+1/2=1/32

Answer

LHS = (4^1/3)^(4x+1)/2

=(4)^(4x+1)/6

= (2)^(4x+1)/ 3

RHS = 1/32

= 1/(2^5)

= 2^(-5)

LHS = RHS

SO, 2^(4x+1)/3 = 2^(-5)

=> (4x+1)/3 = -5 { as bases on both the sides are equal, so exponents are to be equal)

=> 4x+1 = -15

=> 4x = -16

=> x= -4 ……………..ANS

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