Question

(↑3√4)^2x+1/2=1/32

find the value of x​

Answer 1

LHS = (4^1/3)^(4x+1)/2

=(4)^(4x+1)/6

= (2)^(4x+1)/ 3

RHS = 1/32

= 1/(2^5)

= 2^(-5)

LHS = RHS

SO, 2^(4x+1)/3 = 2^(-5)

=> (4x+1)/3 = -5 { as bases on both the sides are equal, so exponents are to be equal)

=> 4x+1 = -15

=> 4x = -16

=> x= -4 ……………..ANS

Answer 2

4^1/3(4x+1/2) = 2^-5

4^((4x+1)/6) = 2^-5

2^2((4x+1)/6) = 2^-5

2^((4x+1)/3) = 2^-5

So base are same ,

4x+1/3 = -5

4x+1 = -15

4x =-16

x = -4.. .

Hope it help u.....