Question

3/4{(3^2-1/3!x^33^4-1/5!x^5+....+(-1)3^2n-1/(2n+1)!x^2n+1..}=sin^3x

Answer 1

Answer:

Step-bAustin3434 Helping Hand

here,

maximum outcomes:36

possible outcomes as product of prime

numbers: (1,2), (2,1), (1,3), (3,1), (1,5), (5,1).

therefore P(getting product a prime number)

=>6/36

=>1/6

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