Question

(-3/4)^3*(3/2)^-2+1*(-10)^0​

Answer 1

Answer:

$\frac{13}{16}$

Step-by-step explanation:

$( \frac{ - 3}{4} )^{3} \times { (\frac{3}{2}) }^{ - 2} + (1 \times {10}^{0} ) = \frac{ - 27}{64} \times \frac{4}{9} + 1 \times 1 = \frac{ - 3}{16} + 1 = \frac{ 13}{16}$

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