Math, asked by ayubmoblies, 1 year ago

(-3)^4-(√(4&3))^0x (-2)^5 ÷ (64)^(2/3)​

Answers

Answered by akanshaagrwal23
2

Step-by-step explanation:

#64 = 4^3#, so we find:

#64^(3/2) = (4^3)^(2/3) = 4^(3*2/3) = 4^2 = 16#

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