Question

(3/4√5-√3) + (2/4√5+√3) = a √5 + b√3. Find the values of a and b.

Answer 1

Here is the answer
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Answer 2

Answer:

Value of a = 5/4 and b=0.

Step-by-step explanation:

Given: $(\frac{3}{4}\sqrt{5}-\sqrt{3})+(\frac{2}{4}\sqrt{5}+\sqrt{3})=a\sqrt{5}+b\sqrt{3}$

To find: Value of a and b.

Consider,

$(\frac{3}{4}\sqrt{5}-\sqrt{3})+(\frac{2}{4}\sqrt{5}+\sqrt{3})$

$=\frac{3}{4}\sqrt{5}+\frac{2}{4}\sqrt{5}-\sqrt{3}+\sqrt{3}$

$=(\frac{3}{4}+\frac{2}{4})\sqrt{5}+0$

$=\frac{5}{4}\sqrt{5}+0\sqrt{3}$

Now by comparing with RHS, we get

a = 5/4 and b = 0

Therefore, value of a = 5/4 and b=0.