Question

(3/4)⁶×(16/9)³=(4/3)^x+2 find x



${ \frac{3}{4} }^{6} \times { \frac{16}{9} }^{3} = { \frac{4}{3} }^{x + 2}$
please answer quickly its a humble request​

Answer 1

The required value of x is -5. I've used the following laws of exponents :

• aᵐ × aⁿ = aᵐᐩⁿ

• (a/b)ᵐ = (b/a)ᐨᵐ

Hope it helps!