Math, asked by haseenakolakkodan, 10 months ago

(3/4)^6*(16/9)^5=(16/9)^x+2

Answers

Answered by AdithyaMahesh17
2

Answer:

x = 0

Step-by-step explanation:

(3/4)^6 * (16/9)^5 = (16/9)^x + 2

= (3/4)^6 * (4/3)^10 = (4/3)^2x + 4

= (4/3)^4 = (4/3)^2x + 4

Bases are same so ignore them

= 4 = 2x + 4

2x = 0

x = 0

Answered by harshal2602
0

Answer-

x = 0

Step-by-step explanation:

(3/4)^6 * (16/9)^5 = (16/9)^x + 2

= (3/4)^6 * (4/3)^10 = (4/3)^2x + 4

= (4/3)^4 = (4/3)^2x + 4

Bases are same so ignore them

= 4 = 2x + 4

2x = 0

x = 0

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