Question

3^4 + 6x^3+4÷x+6please answer it as fast as possible

Answer 1

Step-by-step explanation:

3^4 + 6x^3+4÷x+6

=  $\frac{3^4+6x^3+4}{x+6}$

=  $\frac{6x^3+85}{x+6}$

answer is  $\frac{6x^3+85}{x+6}$

                             or

3^4 + 6x^3+4÷x+6

= $3^4+6x^3+\frac{4}{x}+6$

= 3^4 = 81

= $81+6x^3+\frac{4}{x}+6$

= $6x^3+\frac{4}{x}+81+6$

= 81 + 6 =87

= $6x^3+\frac{4}{x}+87$

answer is $6x^3+\frac{4}{x}+87$