Question

3/4-√7 Rationalise the denomination​

Answer 1

Answer:

$\frac{3}{4-\sqrt{7} }$

Multiply both numerator and denominator by conjugate of denominator,

$\frac{3}{4-\sqrt{7} } * \frac{4+\sqrt{7} }{4+\sqrt{7} }$

$\frac{3(4+\sqrt{7}) }{16-7}$

$\frac{3(4+\sqrt{7}) }{9}$

$\frac{\sqrt{7}+4 }{3}$